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Le Kiet
Software Engineer | Data Scientist
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donut ver two

· One min read
Le Kiet
Software Engineer | Data Scientist
Andy Sloane
A very cool person
_,x,y,o       ,N;char       b[1840]       ;p(n,c)
{for(;n --;x++) c==10?y +=80,x=
o-1:x>= 0?80>x? c!='~'? b[y+x]=
c:0:0:0 ;}c(q,l ,r,o,v) char*l,
*r;{for (;q>=0; )q=("A" "YLrZ^"
"w^?EX" "novne" "bYV" "dO}LE"
"{yWlw" "Jl_Ja|[ur]zovpu" "" "i]e|y"
"ao_Be" "osmIg}r]]r]m|wkZU}{O}" "xys]]\
x|ya|y" "sm||{uel}|r{yIcsm||ya[{uE" "{qY\
w|gGor" "VrVWioriI}Qac{{BIY[sXjjsVW]aM" "T\
tXjjss" "sV_OUkRUlSiorVXp_qOM>E{BadB"[_/6 ]-
62>>_++ %6&1?r[q]:l[q])-o;return q;}E(a){for (
o= x=a,y=0,_=0;1095>_;)a= " <.,`'/)(\n-" "\\_~"[
c (12,"!%*/')#3" "" "+-6,8","\"(.$" "01245"
" &79",46)+14], p("" "#$%&'()0:439 "[ c(10
, "&(*#,./1345" ,"')" "+%-$02\"! ", 44)+12]
-34,a); }main(k){float A=0,B= 0,i,j,z[1840];
puts("" "\x1b[2J");;; for(;; ){float e=sin
(A), n= sin(B),g=cos( A),m= cos(B);for(k=
0;1840> k;k++)y=-10-k/ 80 ,o=41+(k%80-40
)* 1.3/y+n,N=A-100.0/y,b[k]=".#"[o+N&1], z[k]=0;
E( 80-(int)(9*B)%250);for(j=0;6.28>j;j +=0.07)
for (i=0;6.28>i;i+=0.02){float c=sin( i), d=
cos( j),f=sin(j),h=d+2,D=15/(c*h*e+f *g+5),l
=cos(i) ,t=c*h*g-f*e;x=40+2*D*(l*h* m-t*n
),y=12+ D *(l*h*n+t*m),o=x+80*y,N =8*((f*
e-c*d*g )*m -c*d*e-f*g-l*d*n) ;if(D>z
[o])z[o ]=D,b[ o]=" ." ".,,-+"
"+=#$@" [N>0?N: 0];;;;} printf(
"%c[H", 27);for (k=1;18 *100+41
>k;k++) putchar (k%80?b [k]:10)
;;;;A+= 0.053;; B+=0.03 ;;;;;}}

(as with the first one, compile it with -lm, and it needs ANSI-ish terminal emulation)

have a donut

· One min read
Le Kiet
Software Engineer | Data Scientist
Andy Sloane
A very cool person

(compile with gcc -o donut donut.c -lm, and it needs ANSI- or VT100-like emulation)

             k;double sin()
,cos();main(){float A=
0,B=0,i,j,z[1760];char b[
1760];printf("\x1b[2J");for(;;
){memset(b,32,1760);memset(z,0,7040)
;for(j=0;6.28>j;j+=0.07)for(i=0;6.28
>i;i+=0.02){float c=sin(i),d=cos(j),e=
sin(A),f=sin(j),g=cos(A),h=d+2,D=1/(c*
h*e+f*g+5),l=cos (i),m=cos(B),n=s\
in(B),t=c*h*g-f* e;int x=40+30*D*
(l*h*m-t*n),y= 12+15*D*(l*h*n
+t*m),o=x+80*y, N=8*((f*e-c*d*g
)*m-c*d*e-f*g-l *d*n);if(22>y&&
y>0&&x>0&&80>x&&D>z[o]){z[o]=D;;;b[o]=
".,-~:;=!*#$@"[N>0?N:0];}}/*#****!!-*/
printf("\x1b[H");for(k=0;1761>k;k++)
putchar(k%80?b[k]:10);A+=0.04;B+=
0.02;}}/*****####*******!!=;:~
~::==!!!**********!!!==::-
.,~~;;;========;;;:~-.
..,--------,*/

(This was my first attempt at obfuscated C and I feel it's pretty amateurish; se Donut Marke II for a more impressive demo — though this one is simple and elegant in comparison.)